What is the osmotic pressure of 5.58% NaCl aqueous solution at 300K wh

1.	What is the osmotic pressure of 5.58% NaCl aqueous solution at 300K when it is 50%ionised?
Answer» 0·585 % (m/m)NaClmeans that we have 0.585 gNaClin 100 g solution The solution is so dilute that we can assume thedensityis the same as that of water. Thus, we have 0.585 gNaClin 100 mL of solution. c=0.585g NaCl100mL solution×1000mL solution1 L solution×1 mol NaCl55.84g NaCl=0.1048 mol/L Also,i=2forNaCl. Hence, Π=icRT=2×0.01048mol⋅L-1×0.083 14 bar⋅L⋅K-1mol-1×300K=5.23 bar

What is the osmotic pressure of 5.58% NaCl aqueous solution at 300K when it is 50%ionised?

Answer»

0·585 % (m/m)NaClmeans that we have 0.585 gNaClin 100 g solution

The solution is so dilute that we can assume thedensityis the same as that of water.

Thus, we have 0.585 gNaClin 100 mL of solution.

c=0.585g NaCl100mL solution×1000mL solution1 L solution×1 mol NaCl55.84g NaCl=0.1048 mol/L

Also,i=2forNaCl.

Hence,

Π=icRT=2×0.01048mol⋅L-1×0.083 14 bar⋅L⋅K-1mol-1×300K=5.23 bar