What is the oxidation number of iron in the brown ring complex compoun

1.	What is the oxidation number of iron in the brown ring complex compound?
Answer» Solution :The BROWN RING COMPLEX compound is given as : `[Fe(H_(2)O)_(5)NO] SO_(4)` The complex ion is `[Fe(H_(2)O)_(5)NO]^(2+)` Oxidation NUMBERS of `H_(2)O` is zero and `NO` is `+1`. Oxidation STATE of Fe is `+1` Experimentally, the number of unpaired electrons also support `+1` state of Fe (but not `+2` state).

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