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What is the oxidation number of Mn is MnO_(4)^(-)? |
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Answer» Solution :Mn in `MnO_4^(-)` , Let the oxidation number of Mn in `MnO_4^(-)` be X. WRITING oxidation number of each atom above its symbol, we get, `OVERSET(x)(Mn)overset(-2)O_4i.e., x+4(-2)=-1i.e., x=+7` Thus, the oxidation number of Mn in `MnO_4^(-)` is +7 |
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