1.

What is the oxidation number of phosphorous in calcium phosphide ?

Answer»

<P>`-5`
`-3`
`+5`
`+3`

Solution :`Ca_(3)P_(2)rArr3(CA)+2(x)=0`
`therefore3(+2)+2(x)=0`
`therefore2x=-6" "thereforex=-3`


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