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What is the Oxidation number of S in H2S2O8. |
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Answer» Two oxygen atoms are involved in peroxide bonding in the H2S2O8 structure, so the oxidation number would be -1each. The remaining atoms of oxygen would have a charge of -2. We can therefore determine the state of oxidation of sulphur (x) as shown in: H2S2O8 ⇒ 2+2x+[-2] × 6+[-1] × 2 ⇒ 2x – 12 ⇒ 2x – 12 = 0 ⇒ 2x = 12 ⇒ x = 12/2 x = 6 |
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