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What is the Oxidation number of sulphur in Perdisulphuric acid ? |
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Answer» `+4` The two .O. atoms of peroxy bonds have (-1) OXIDATION state. `H_(2)S_(2)O_(8)=2H+6(O)+2O` of peroxybond + 2(s) `therefore0=2(+1)+6(-2)+2(-1)+2(S)` `therefore` 2(S) = -12 `thereforeS=+6` |
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