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What is the oxidation number of sulphur in the following molecules/ ions SO_4^(2-) |
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Answer» SOLUTION :In `SO_4^(2-)` LET x be oxidation number of S, Oxidation number of Oxygen is -2. `S O_4^(2-)` Let oxidation number be x -2 `THEREFORE (1 times x)+ (4 times -2)=-2 implies x-8=-2 implies x=-2+8 implies x=6` Oxidation number of S in `SO_4^(2-)` is +6. |
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