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What is the oxidation number of sulphur in the following molecules/ ions H_2SO_4 |
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Answer» Solution :In `H_2SO_4` LET X,+1 ,-2 be oxidation NUMBER of S, H and O Let ON Be  i.e., `(+1 times 2)+ (x times 1)+(-2 times 4)=0` `implies (1 times 2)+x+ (-2 times 4) =0 , 2+ x-8=0, x=+6` Oxidation number of S in `H_2SO_4`is +6. |
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