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What is the oxidation number of the metal atom in the following ions? `(i) [Fe(CN)_(6)]^(3) ,(ii) MnO_(4), (iii) [Cr(H_(2)O)_(6)]^(3^(+)` |
Answer» `(i) Fe in [Fe(CN)_(6)]^(3^(+))ion` In this ion, the oxidation number of CN ions is -1 Let the oxidation number of Fe ber x. write the oxidation number of Fe above its symbol and that of `CN^(-)` ion above its formula. `overset(x)Feoverset(-1)(CN)_(6)` Caclulate the oxidation num,bners of all the species `x+6(-1)=x-6` Since `[Fe(CN)_(6)]^(3)` is an anion the sum of the oxidation j number must be -3 `x-6=-3 or x=+3.` `(ii) Mn in MnO_(4)` ion Let the oxidation number of atoms above their symbols `overset(x)Mn overset(-2)O_(4)` Calculate the oxidation number of all the atoms since `[MnO_(4))]` is an anion , the sum of the oxidation numbers must bve-1 `therefore x-8=-1 orx=-21+8=+7` `Cr in [Cr(H_(2)O)_(6)]^(3+) ion` As `H_(2)O` is a neurtral molecule its oxidation number is taken as 0 Write the oxidation number of `Cr` above its symbol and that of `H_(2)O` above its formula. `overset(x)Croverset(O)(H_(2))O_(6)` Since `[Cr(H_(2)O)_(6)]^(3+)` is an ion , the sum of the oxidation numbers must be+3 `x=+3` |
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