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What is the oxidation number of the metals [Fe(CN)_6]^(4-) |
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Answer» Solution :Fe in `[Fe(CN)_6]^(4-)` . LET the oxidation number of Fe in `[Fe(CN)_6]^(4-)` be x and CN be -1 i.e., `oversetx(Fe)OVERSET(-)((CN))_6` `therefore` SUM of oxidation number of all the atoms in `[Fe(CN)_6]^(4-)=x+6(-1)=-4,x-6=-4,x=+2` Thus, the oxidation number of Fe in `[Fe(CN)_6]^(4-)` is +2. |
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