What is the oxidation number of underlined nitrogen in NH_(4)underline

1.	What is the oxidation number of underlined nitrogen in NH_(4)underlineNO_(3) ?
Answer» `-3` `+3` `+5` `-1` Solution :`NH_(4)NO_(3)` `NH_(4)+N+3(O)=0` `therefore+1+N+3(-2)=0` `thereforeN=6-1=+5`

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