1.

What is the oxidation potential of given hydrogen half cel at 1 bar pressure and 25^(@)C temperature? Pt|underset("1 bar")(H_(2(g)))|HCl_((aq))pH=3

Answer»

`0.059V`
`0.188V`
`0.177V`
`0.000`V

Solution :`Pt|underset(1" BAR")(H_(2(g))|HCl_((aq))pH=3`
So, `[H^(+)]=1xx10^(-3)M=0.001M`
And reaction : `underset("1 bar")(H_(2(g))) to underset(0.001M)(2H_((aq))^(+))+2e`
According to Nernest.s formula,
`E_(CELL)=E_(H^(+)//H_(2))^(Theta)-(0.059)/(n)"log"([H^(+)]^(2))/([H_(2)])`
`=0.0-(0.059)/(2)"log"((0.001)^(2))/(1)`
`=0.0295xx(-6.0)`
`=+0.177V`


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