1.

What is the oxidation state and hybridisation of boron in compound formed when BCl_(3) undergoes reaction with the water?

Answer»

`3, sp^(2)d`
`3, sp^(3)`
`4, sp^(3)`
`3, sp^(2)d`

SOLUTION :`BCl_(3)` FORMS `[B(OH)_(4)]^(-)` in which B is `sp^(3)` hybridised and have +3 oxidation STATE.


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