1.

What is the oxidation state of `Fe` and `NO` in nitroprusside ion. How can it be determined?

Answer» The nitroprusside ion is `[Fe(CN)_(5)NO]^(2-)`. This can be established by measuring the magnetic moment of the solid compound which should correspond to `(Fe^(2+)=3d^(6))`, that is, four unpaired electrons. In this ion, iron is in `Fe^(2+)` and `NO` is `NO^(+)`.


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