1.

What is the oxidation State of ‘S’ in H2S2O6.

Answer»

O.N. of S in H2S2O6

Let O.N. of S = x

2(4 - 1) + 2x + 6( - 2) = 0

⇒ x = +5

Hence, oxidation number of ‘S’ in H2S2O6 = +5



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