What is the oxidation state of sulphur in (NH_(4))_(2)S_(2)O_(8) ?

1.	What is the oxidation state of sulphur in (NH_(4))_(2)S_(2)O_(8) ?
Answer» 5 6 4 7 Solution :(i) `(NH_(4))_(2)S_(2)O_(8)` It has `2NH_(4)^(+)andS_(2)O_(8)^(2-)` IONS. (ii) `S_(2)O_(8)^(2-)` has one peroxy - O - O - BOND in which two oxygen atoms are in (-1) state, Remained six .O. atoms have -2 oxidation number. `therefore2S+2(O)+6(O)=-2` `therefore2x+2(-1)+6(-2)=-2` `therefore2x-2-12=-2` `therefore2x=+12` `thereforex=+6` The two .O. atoms have (-1) oxidation number

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