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What is the percentage of calcium in calcium carbonate `(CaCO_(3))` ? |
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Answer» Molecular mass of `CaCO_(3) = 40 + 12 + 3 xx 16 = 100 ` amu . Mass of calcium in 1 mol of `CaCO_(3) = 40`g `therefore` percentage of calcium = `(40 xx 100)/(100) = 40` . |
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