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What is the percentage strength of a solution of 100 volume `H_(2)O_(2)`? |
Answer» 100 volume solution means that 1L of this `H_(2)O_(2)` solution will give 100 L of oxygen at STP `underset(2xx34g=68g)(2H_(2)O_(2))to2H_(2)O+underset(22.7L" at STP")(O_(2))` From equation, 22.7 of `O_(2)` at STP is obtained from `H_(2)O_(2)=68g` 100 L of `O_(2)` at STP is obtained from `H_(2)O_(2)=(68)/(22.7)xx100` `=299.55g//L` `=30%" "H_(2)O_(2)` solution |
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