What is the pH at the equivalenve point for the titration of 0.20 M aniline (K_(b) = 7.95 xx 10^(-10)) with 0.20 M HCL

What is the pH at the equivalenve point for the titration of 0.20 M an

1.	What is the pH at the equivalenve point for the titration of 0.20 M aniline (K_(b) = 7.95 xx 10^(-10)) with 0.20 M HCL
Answer» `2.8` `11.1` `5.2` `9.42` Solution :At the equivalence POINT in the titration of weak base and strong acid, it is the salt that is formed whichundergoes HYDROLYSIS `:. pH = 7 - (1)/(2) pK_(b) - 1/2 "LOG"C`