1.

What is the pH of 1MNaPO_(4) solution at 25^(@)C? PO_(4)^(3-)+H_(2)OhArrHPO_(4)^(2-)+OH^(-),K_(b)=2.4xx10^(-2) Assume no hydrolysis of HPO_(4)^(2-) ions.

Answer»

SOLUTION :`K_(a)=(x^(2))/(1-x)=2.4xx10^(-2)`
`x^(2)+(2.4xx10^(-2))xx-2.4xx10^(-2)=0`
`x=0.143=[OH^(-)]`
`[H^(+)]=(K_(w))/([OH^(-)])=7xx10^(-14)M`
`:.pH=13.15`


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