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What is the pH of a 0.05 M solution of formic acid? (K_(a)=1.8xx10^(-4)) |
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Answer» Solution :`[H^(+)]=SQRT(K_(a)*C)=sqrt(1.8xx10^(-4)xx0.05)=3.00xx10^(-3)"mol"dm^(-3)` `pH=-log[H^(+)]=-log(3.0xx10^(-3))=2.52`. |
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