1.

What is the pH of a 1 M CH_(3)COOH a solution K_(a) of acetic acid = 1.8 xx 10^(-5) K = 10^(-14) mol^(2) "litre"^(-2)

Answer»

9.4
4.8
3.6
2.4

Solution :`CH_(3)COO^(-) + H_(2)O hArr CH_(3)COOH + OH^(-)`
`:. [OH^(-)] = c XX h`
`h = sqrt((K_(w))/(K_(a)) xx C) = sqrt((10^(-14))/(1.8 xx 10^(-5)) xx 1) = 2.35 xx 10^(-5)`
`:. pOH = 4.62 , pH = 9.38 ~~ 9.4`.


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