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What is the pH of a buffer solution prepared by dissolving 0.1 mole of sodium acetate and 0.2 mole of acetic acid in enough water to make a dm^(3) of solution? (K_(a) of acetic acid = 1.8xx10^(-5)). |
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Answer» Solution :`pK_(a)=-logK_(a)` = `-log1.8xx10^(-5)` = -(5.2553) = 4.7447 `pH=pK_(a)+"LOG"(["salt"])/(["ACID"])` = `4.74+"log"0.1/0.2` = `474+log0.5` = 4.74 - 0.3010 = 4.44 |
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