1.

What is the pH of a buffer solution prepared by dissolving 0.1 mole of sodium acetate and 0.2 mole of acetic acid in enough water to make a dm^(3) of solution? (K_(a) of acetic acid = 1.8xx10^(-5)).

Answer»

Solution :`pK_(a)=-logK_(a)`
= `-log1.8xx10^(-5)`
= -(5.2553)
= 4.7447
`pH=pK_(a)+"LOG"(["salt"])/(["ACID"])`
= `4.74+"log"0.1/0.2`
= `474+log0.5`
= 4.74 - 0.3010
= 4.44


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