What is the pH of a solution obtained by dissolving 0.0005 mole of the strong electrolyte, calcium hydroxide, Ca(OH)_(2) , to form 100 ml of a saturated solution (aqueous)? (K_(w)=1.0xx10^(-14) "mole"^(2) "litre"^(-2))

What is the pH of a solution obtained by dissolving 0.0005 mole of the

1.	What is the pH of a solution obtained by dissolving 0.0005 mole of the strong electrolyte, calcium hydroxide, Ca(OH)_(2) , to form 100 ml of a saturated solution (aqueous)? (K_(w)=1.0xx10^(-14) "mole"^(2) "litre"^(-2))
Answer» `9.8` ` 11.7` ` 12.0 ` ` 3.0 ` Solution :` M= ( 5 XX 10 ^(-4) )/(100)xx 1000 = 5 xx 10 ^(-3) ` ` THEREFORE N= M xx n = 0.01 M` ` [OH^(-)] =10 ^(-2)N rArr pOH =2rArr pH =12`