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What is the pH of a solution obtained by mixing 10 mL of 0.1 M HCl and 40 mL 0.2 M `H_(2)SO_(4)` ?A. 0.74B. 7.4C. 4.68D. 0.468

Answer» Correct Answer - D
Millimoles of `H^(+)` from `HCl=0.1xx10=1`
Millimoles of `H^(+)` from `H_(2)SO_(4)=0.2xx40xx2=16`
Conc. Of `H^(+)=("Millimoles")/("Volume")=(16+1)/(40+10)=(17)/(50)=0.34`
`pH=-log[H^(+)]=-log(0.34)=0.468`


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