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What is the pH of the resulting solution when equal volumes of 0.1 MNaOH and 0.01 M HCl are mixed? |
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Answer» `7.0` 100ML of 0.1 M NaOH contain NaOH `=100xx0.1` MMOL = 10 mmol `100 mL` of0.01 M HCl contain HCl `=100xx0.01` mmol = 1 mmol 1 mmol of HCl will neutralize 1 mmol of NaOH `:.` NaOH LEFT unneutralized in the solution = 9 mmol Volume of solution after mixing = 200 mL `:.` Molarityof NaOH in the final solution `=(9)/(200) M = 0.045M ` `pOH = -log (0.045) = 1.35` `pH = 14-1.35 = 12.65` |
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