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What is the pH of the resulting solution when equal volumes of 0.1 M NaOH and 0.01 M HCl are mixed ? |
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Answer» `7.0` 0.1 X 1 - 0.01 x 1 = N x 2 `[OH^-]=N_R=0.09/2`=0.045 N pOH=-log (0.045) = 1.35 `therefore` pH=14-pOH=14-1.35 = 12.65 |
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