1.

What is the pH of the resulting solution when equal volumes of 0.1 M NaOH and 0.01 M HCl are mixed ?

Answer»

`7.0`
`1.04`
`12.65`
`2.0`

SOLUTION :`N_1V_1-N_2V_2=N.V.`
0.1 X 1 - 0.01 x 1 = N x 2
`[OH^-]=N_R=0.09/2`=0.045 N
pOH=-log (0.045) = 1.35
`therefore` pH=14-pOH=14-1.35 = 12.65


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