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What is the phase excitation difference for an end-fire array?(a) 0(b) ±kd /2(c) π(d) ±kdI had been asked this question during an internship interview.I'm obligated to ask this question of End Fire Array topic in division Antenna Array of Antennas

Answer»

Right option is (d) ±kd

Best EXPLANATION: The MAXIMUM array factor occurs when \(\FRAC{sin \frac{Nφ}{2}}{\frac{Nφ}{2}}\) maximum that is \(\frac{Nφ}{2}=0. \)

And φ=kdcosθ+β

=> kdcosθ+β=0 For an end-fire array maximum RADIATION is along the axis of array so

 θ=0° or 180°

=> β=kd when θ=180°

=> β=-kd when θ=0°



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