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What is the phase excitation difference in end-fire array with array spacing d atθ=0°?(a) \(-\frac{2π}{λ} d \)(b) \(\frac{2π}{λ} d \)(c) \(-\frac{π}{λ} d \)(d) \(\frac{π}{λ} d \)This question was addressed to me in an interview for internship.I'm obligated to ask this question of End Fire Array in portion Antenna Array of Antennas

Answer»

The CORRECT choice is (a) \(-\frac{2π}{λ} d \)

EASIEST explanation: In end-fire array the PHASE excitation difference is –kd for θ=0°.

kdcosθ+β=0

β=-kd

\(β=-\frac{2π}{λ} d \)



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