1.

What is the potential of a cell containing two hydrogen electrodes the negative one in contact with 10^(-8)M" "H^(+) and positive one in contact with 0.025 M H^(+)

Answer»

0.18 V
0.28 V
0.38V
0.48V

Solution :`(1)/(2)H_(2)toH^(+)(10^(-8)M)+E^(-)` (oxidation)
`H^(+)(0.025M)+e^(-)to(1)/(2)H_(2)` (REDUCTION)
Cell REACTION is:
`H^(+)(0.025M)toH^(+)(10^(-8)M),E_(cell)=0.38V`


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