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What is the potential of a cell containing two hydrogen electrodes the negative one in contact with `10^(-8)M" "H^(+)` and positive one in contact with 0.025 M `H^(+)`A. 0.18 VB. 0.28 VC. 0.38VD. 0.48V |
Answer» Correct Answer - C `(1)/(2)H_(2)toH^(+)(10^(-8)M)+e^(-)` (oxidation) `H^(+)(0.025M)+e^(-)to(1)/(2)H_(2)` (reduction) Cell reaction is: `H^(+)(0.025M)toH^(+)(10^(-8)M),E_(cell)=0.38V` |
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