1.

What is the potential of the cell containing two hydrogen electrodes as represented below ? Pt | (1)/(2) H_(2) (g) | H^(+) (10^(-8)M) ||H^(+) (0.001M) | (1)/(2) H_(2) (g) | Pt

Answer»

`-0.295` V
`-0.0591` V
0.295
0.0591 V

Solution :`E_(cell) = (0.0592)/(1) log ([H^(+)]_(RHS))/([H^(+)]_(LHS))`
` = 0.0592 log_(10) (10^(-3))/(10^(-8)) = 0.0592 xx 5 = 0.295` V


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