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What is the potential of the cell containing two hydrogen electrodes as represented below ? `Pt | (1)/(2) H_(2) (g) | H^(+) (10^(-8)M) ||H^(+) (0.001M) | (1)/(2) H_(2) (g) | Pt`A. `-0.295` VB. `-0.0591` VC. 0.295D. 0.0591 V

Answer» Correct Answer - C
`E_(cell) = (0.0592)/(1) log ([H^(+)]_(RHS))/([H^(+)]_(LHS))`
` = 0.0592 log_(10) (10^(-3))/(10^(-8)) = 0.0592 xx 5 = 0.295` V


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