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What is the pressure exerted by 10^(23) gas molecules, each molecule of mass 10^(-23)g, present in a container of volume one L and RMS speed of 1000 m s^(-1)? |
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Answer» Solution :KINETIC GAS equation `PV = (1)/(3) mnC^(2)` Pressure of the gas (P) ` = (mnC^(2))/(3V) = (10^(-23) xx 10^(23) xx 10^(10))/(3 xx 1000) = 3.33 xx 10^(8)` dyne `cm^(-2)` |
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