What is the pressure of 2 mole of NH_(3) at 27^(@)C when its volume is 5 litre in van der Waals equation ? (a=4.17, b=0.03711)

What is the pressure of 2 mole of NH_(3) at 27^(@)C when its volume is

1.	What is the pressure of 2 mole of NH_(3) at 27^(@)C when its volume is 5 litre in van der Waals equation ? (a=4.17, b=0.03711)
Answer» <P>10.33 atm 9.33 atm 9.74 atm 9.2 atm Solution :`(P+(an^(2))/(V))(V-nb)=NRT` or `P=(nRT)/(V-nb)-(an^(2))/(V^(2))` `=(2xx0.0821xx300)/(5-2xx0.03711)-(4.17xx2^(2))/(5^(2))` `10-0.66=9.33" atm"`