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What is the pressure of 2 mole of `NH_(3)` at `27^(@)C` when its volume is 5 litre in van der Waals equation ? (a=4.17, b=0.03711)A. 10.33 atmB. 9.33 atmC. 9.74 atmD. 9.2 atm |
Answer» Correct Answer - B `(P+(an^(2))/(V))(V-nb)=nRT` or `P=(nRT)/(V-nb)-(an^(2))/(V^(2))` `=(2xx0.0821xx300)/(5-2xx0.03711)-(4.17xx2^(2))/(5^(2))` `10-0.66=9.33" atm"` |
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