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What is the pressure of `2 "moles"` of `NH_(3)` at `27^(@)C` when its voulume is `5 "litre"` in van der waals equation `(a= 4,17,b= 0.03711)`?A. `10.33 atm`B. `9.33 atm`C. `9.74 atm`D. `9.2 atm` |
Answer» Correct Answer - B `(P-(n^(2)a)/(V^(2)))(V-nb)=nRT` `(P-((2)^(2)xx4.17)/((5)^(2)))(5-2xx.03711)` `=2xx.0821xx300` `P=(2xx.0821xx300)/(5-2xx0.3711)-(4.7xx2^(2))/(5^(2))` `implies 10-0.66= 9.3 atm` |
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