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What is the pressure on a swimmer 10 m below the surface of a lake ? (Density of water = 10^(3)kgm^(-3) , Acceleration of gravity g=10ms^(-2) and atm pressure P_(a)=1.01xx10^(5)Pa) |
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Answer» Solution :Depth from the surface of lake H= 10 m Density of water `rho=10^(3)kgm^(-3)` Acceleration of gravity `g=10ms^(-2)` Atm pressure `P_(a)=1.01xx10^(5)Pa` Pressure at a depth h from the surface of lake water, `P=P_(a)+hrhog` `=1.01xx10^(5)+10xx10^(3)xx10` `=1.01xx10^(5)+10^(5)` `=2.01xx10^(5)NM^(-2)or 1.99 atm`. Hence , this is a `100%` increase in pressure fromsurface level . At a depth of 1 km the increase in pressure is 100 atm . Submarines are designed to WITHSTAND such enormouspressure . |
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