1.

What is the pressure on a swimmer 10 m below the surface of a lake ? (Density of water = 10^(3)kgm^(-3) , Acceleration of gravity g=10ms^(-2) and atm pressure P_(a)=1.01xx10^(5)Pa)

Answer»

Solution :Depth from the surface of lake H= 10 m
Density of water `rho=10^(3)kgm^(-3)`
Acceleration of gravity `g=10ms^(-2)`
Atm pressure `P_(a)=1.01xx10^(5)Pa`
Pressure at a depth h from the surface of lake water,
`P=P_(a)+hrhog`
`=1.01xx10^(5)+10xx10^(3)xx10`
`=1.01xx10^(5)+10^(5)`
`=2.01xx10^(5)NM^(-2)or 1.99 atm`.
Hence , this is a `100%` increase in pressure fromsurface level . At a depth of 1 km the increase in pressure is 100 atm . Submarines are designed to WITHSTAND such enormouspressure .


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