Saved Bookmarks
| 1. |
What is the pressure on a swimmer 10 m below the surface of a lake? |
|
Answer» Here h = 10 m, Pa = 1.01 x 105 Pa Total pressure = Pa + \(\rho gh\) \(\frac{1}{01} \times 10^5 + 1000 \times 10 \times 10\) 2.01 x 105 Pa ≈ 2 atm |
|