What is the probability of 53 Sunday or 53 Monday in a leap year?ए�

1.	What is the probability of 53 Sunday or 53 Monday in a leap year?एक अधिवर्ष में 53 रविवारों या 53 सोमवारों के होने की प्रायिकता क्या1) ।iv) नेi)।।2 ।।
Answer» Normally, year consists of 365 days .But leap year had 365+1 days . 366 days divided into weekly days has 365/7 i.e. 52 days + 2 extra days. U have t find that two days are Sunday and Monday then we get the 53 Sundays or 53 Mondays. It cleared that weekly days are cyclic. Two days should be one of these sets >[(S,M),(M,T),(T,W),(W,TH),(TH,F),(F,Sa),(Sa,S)]. Therefore ,the probability that getting 53 Sundays and Mondays = the probability that 2 extra days should be sun or mon. There are seven cases that the two days may be happen like that (already shown above). In those, (S,M), (M,T) that has to be happen to get 53 sun or 53 mon days. Therefore,Required probability = 2/7 (ii) is correct option l only ask the sunday

What is the probability of 53 Sunday or 53 Monday in a leap year?एक अधिवर्ष में 53 रविवारों या 53 सोमवारों के होने की प्रायिकता क्या1) ।iv) नेi)।।2 ।।

Answer»

Normally, year consists of 365 days .But leap year had 365+1 days .

366 days divided into weekly days has 365/7 i.e. 52 days + 2 extra days.

U have t find that two days are Sunday and Monday then we get the 53 Sundays or 53 Mondays.

It cleared that weekly days are cyclic.

Two days should be one of these sets >[(S,M),(M,T),(T,W),(W,TH),(TH,F),(F,Sa),(Sa,S)].

Therefore ,the probability that getting 53 Sundays and Mondays = the probability that 2 extra days should be sun or mon.

There are seven cases that the two days may be happen like that (already shown above).

In those, (S,M), (M,T) that has to be happen to get 53 sun or 53 mon days.

Therefore,Required probability = 2/7

(ii) is correct option

l only ask the sunday