What is the probability of throwing a number greater than 2 with a fai

1.	What is the probability of throwing a number greater than 2 with a fair die ?
Answer» Let the experiment is throwing a fair die. And the event E is getting a number greater than 2 on the upper face of die. Total number of outcomes = n(S) = 6. Numbers on die which are greater than 2 are 3, 4, 5 and 6 . Therefore, total number of outcomes favourable to event E is n(E) = 4. Now, probability of getting a number greater than 2 = \(\frac{Total \,outcomes\, which\, faurable\, to \, event\, E}{totatl number\, of\, outcomes}\) \(\frac{n(E)}{n(S)} = \frac{4}{6} = \frac{2}{3} = 0.67\) Hence, the probability of throwing a number greater than 2 with a fair die is 0.67.

What is the probability of throwing a number greater than 2 with a fair die ?

Answer»

Let the experiment is throwing a fair die.

And the event E is getting a number greater than 2 on the upper face of die.

Total number of outcomes = n(S) = 6.

Numbers on die which are greater than 2 are 3, 4, 5 and 6 .

Therefore, total number of outcomes favourable to event E is n(E) = 4.

Now, probability of getting a number greater than 2 = \(\frac{Total \,outcomes\, which\, faurable\, to \, event\, E}{totatl number\, of\, outcomes}\)

\(\frac{n(E)}{n(S)} = \frac{4}{6} = \frac{2}{3} = 0.67\)

Hence, the probability of throwing a number greater than 2 with a fair die is 0.67.

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