What is the probability that a leap year has 53 Sundays and 53 Mondays

1.	What is the probability that a leap year has 53 Sundays and 53 Mondays?
Answer» Given: a leap year which includes 52 weeks and two days Formula: P(E) = \(\frac{favourable \ outcomes}{total \ possible \ outcomes}\) so, we have to determine the probability of that remaining two days are Sunday and Monday S= {MT, TW, WT, TF, FS, SSu, SuM} Therefore n(S)=7 E= {SuM} n(E)=1 P(E) = \(\frac{n(E)}{n(S)}\) P(E) = \(\frac{1}{7}\)

What is the probability that a leap year has 53 Sundays and 53 Mondays?

Answer»

Given: a leap year which includes 52 weeks and two days

Formula: P(E) = \(\frac{favourable \ outcomes}{total \ possible \ outcomes}\)

so, we have to determine the probability of that remaining two days are Sunday and Monday

S= {MT, TW, WT, TF, FS, SSu, SuM}

Therefore n(S)=7

E= {SuM}

n(E)=1

P(E) = \(\frac{n(E)}{n(S)}\)

P(E) = \(\frac{1}{7}\)

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What is the probability that a leap year has 53 Sundays and 53 Mondays?

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