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What is the projection of `vecA` on `vecB` ?A. `vecA.vecB`B. `vecA.hatB`C. `vecB.vecA`D. `vecA.hatB`

Answer» Correct Answer - B
Projection of `vecA` on `vecB` is A `cos theta` in direction of `vecB` ltbr. `vecA,vecB=AB cos thetarArrA cos theta =(vecA.vecB)/(B)=vecA.hatB`


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