What is the purity of concentrated H 2 SO 4 solution (d=1.8gm/

1.	What is the purity of concentrated H 2 SO 4 solution (d=1.8gm/mol) if 5 ml of these solution is neutralized by 84.5 ml of 2N NaOH solution
Answer» Answer: H 2 SO 4 +2NaOH→Na 2 SO 4 +2H 2 O Moles of NaOH required = 1000 2×84.5 =0.169 For 2 moles NaOH→1 MOLE H 2 SO 4 is USED For 0.169 mole NaOH→0.0845 moles are used. Mass of H 2 SO 4 →0.0845×98=8.281 gm (Theoretical) Mass of H 2 SO 4 used in original reaction ⇒5×1.8=9 gm ∴ % purity = 9 8.281 ×100=92.12 %

What is the purity of concentrated H 2 SO 4 solution (d=1.8gm/mol) if 5 ml of these solution is neutralized by 84.5 ml of 2N NaOH solution

Answer»

Answer:

+2NaOH→Na

+2H

Moles of NaOH required =

1000

2×84.5

=0.169

For 2 moles NaOH→1 MOLE H

For 0.169 mole NaOH→0.0845 moles are used.

Mass of H

→0.0845×98=8.281 gm (Theoretical)

Mass of H

used in original reaction ⇒5×1.8=9 gm

∴ % purity =

8.281

×100=92.12 %