1.

What is the quantity of electricity (in columbs) required to deposit all the silver from 250mL of 1M AgNO_(3) solution ? (Ag=10R)

Answer»

2412.5
24125
4825
28250

Solution :Amount of AG in solution =MxxV (mL)
`=1xx250=250m ` mol
`=250xx10^(-3)` mol
`=250xx10^( -3)` mol
=0.25mol
`Ag^(+)+e^(-)rarrAg`
1 mol 96500C
REDUCTION of 1 mol of Ag requires 96500C
Reduction of 0.25 mol of Ag requires `=96500xx0.23=24125C`


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