1.

What is the quantity of hydrogen gas liberated when `46 g` sodium reacts with excess ethanol ? (Given atomic mass of `Na = 23`)A. `2.4 xx 10^(-3)` kgB. `2.0 xx 10^(-3)` kgC. `4.0 xx 10^(-3)` kgD. `2.4 xx 10^(-2)` kg

Answer» Correct Answer - B
`2C_(2)H_(5)OH + 2Na to underset("sod. Ethoxide") (2C_(2)H_(5)Ona + H_(2)) uarr`
46 of ef Na means 2 moles of Na liberates one mole of `H_(2)` i.e., 1g molar mass i.e., i.e. `2 xx 10^(3)` kg.


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