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What is the ratio between the energies of two types of radiation whose wavelengths are 6000 Å and 2000 Å respectively. |
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Answer» Solution : `lambda_(1)=6000Å=6xx10^(-7)m` `lambda_(2)=2000Å=2XX10^(-7)m` `(E_(1))/(E_(2))=(hc)/(6xx10^(-7))XX(2xx10^(-7))/(hc)=(1)/(3)` `therefore E_(1):E_(2)=1:3 or E_(2)=3E_(1)` |
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