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What is the ratio of average molecular KE of CO_(2) to that of SO_(2) at 27^(@)C? |
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Answer» Solution :Assume molecules to be spheres with radius r. therefore the volume of molecule is `(4pir^(3))/(3)` The closest APPROACH between TWO molecules =`2r`. Since two molecules cannot come closer than distance 2r. The excluded volume per pair of molecules in binary collision is Volume of sphere of radius `2r=(4)/(3)pi(2r)^(3)=8xx(4pir^(3))/(3)` Excluded volume per molecules is `(1)/(2)[8xx(4pir^(3))/(3)]=4xx(4pir^(3))/(3)` `=4xx`volume of one molecule |
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