1.

what is the ratio of moles of Mg(OH)_(2) and AI(OH)_(3) present in 1 litre saturated aqueous solution of Mg(OH)_(2) and AI(OH)_(3) (Given K_(sp) of Mg(OH)_2)=4xx10^(-12) asnd K_(sp) of AI(OH)_(3) is 1xx10^(-33)).Report your answer after multiplying by 10^(-17) .

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Solution :What is the ratio of …………….
`{:(Mg(OH)_(2),,hArr,Mg^(2+)+2OH^(-)),(,x, 2x+3y),(AI(OH)_(3),hArr,AI^(3+)+3OH^(-)),(,y,3y+2x):}`
Since `K_(ap)` of `Mg(OH)_(2)gt K_(ap)` of `AI(OH)_(3)`
`:. X GTGT y`,`:. 2x+3y~=2x`
`4xx10^(-12)= [Mg^(2+)][OH^(-)]^(2)`
`=x+(2x)^(2)`
`:. x= 10^(-4)`
Similary`1XX10^(-33)=[AI^(3+)][OH^(-)]^(3)`
`1xx10^(-33)=yxx(2x)^(3)`
`:. y = (10^(-21))/(8)`
Thus `(x)/(y) = 8xx10^(17)`
`:.` Ans. `= 8xx10^(+17) = 8`


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