1.

What is the ratio of the radii of the 3rd orbits of He^(+) and Li^(2+) ?

Answer»

SOLUTION :n is constant and its value is 3.
`Z" of "He^(+)=2, Z" of "LI^(2+)=3`
`r_(n)=(0.529xxn^(2))/(Z)Å""(r_(1))/(r_(2))=(Z_(2))/(Z_(1))=(3)/(2) or 3:2`


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