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What is the ratio of the radii of the 3rd orbits of He^(+) and Li^(2+) ? |
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Answer» SOLUTION :n is constant and its value is 3. `Z" of "He^(+)=2, Z" of "LI^(2+)=3` `r_(n)=(0.529xxn^(2))/(Z)Å""(r_(1))/(r_(2))=(Z_(2))/(Z_(1))=(3)/(2) or 3:2` |
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